f in Section 5.1 on page
could have been defined as follows:
f:num->num; f(0) <= 0; f(n+1) <= (n+1)+f(n);We now have two rules for
f. One for when n=0 and the other for when n>0.
To evaluate f(1) we use the second rule.
f(1) matches the left hand side of the second rule with n=0
so to evaluate f(1) we evaluate the right hand side of
the second rule with n=0. This gives (0+1)+f(0)
which is 1+0 which gives 1.
Similarly,
to evaluate f(2) we use the second rule.
f(2) matches the left hand side of the second rule with n=1
so to evaluate f(2) we evaluate the right hand side of
the second rule with n=1. This gives (1+1)+f(1)
which is 2+1 which gives 3. etc.